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trouble with solve - Сообщения
#1 Опубликовано: 10.06.2010 19:09:29
I desire to solve this:
c:12-1,23*(1+x/2)
solve(c;x)=17,512195
I get the value of x, but if I write
c:12-1,23*(1+x/3)
solve(c;x)=
I get the message "no real roots" (in this case the value of x is 26,268292)
Someone can help me to understand why?
Stefano
c:12-1,23*(1+x/2)
solve(c;x)=17,512195
I get the value of x, but if I write
c:12-1,23*(1+x/3)
solve(c;x)=
I get the message "no real roots" (in this case the value of x is 26,268292)
Someone can help me to understand why?
Stefano
#2 Опубликовано: 10.06.2010 21:09:22
Stefano,
Try using the solve function with 4 arguments, where the third and fourth arguments are the lower and upper bounds respectively within which the root may be found. See screenshot below:

Graphing the function can help in choosing a suitable interval for the lower and upper bounds. Please see the following thread and wiki page for more info:
Solve not working
Solve function
BTW: An improved solve function would be a great plugin project for someone to work on.
Maybe someday.
Try using the solve function with 4 arguments, where the third and fourth arguments are the lower and upper bounds respectively within which the root may be found. See screenshot below:

Graphing the function can help in choosing a suitable interval for the lower and upper bounds. Please see the following thread and wiki page for more info:
Solve not working
Solve function
BTW: An improved solve function would be a great plugin project for someone to work on.

Will Massie
Mechanical Engineer
Oregon, USA
#3 Опубликовано: 11.06.2010 16:55:20
Thank you Maweilian,
before posting my question I read only this post http://en.smath.info/forum/default.aspx?g=posts&t=434, so I supposed that the need for an interval was only for non linear equation. I read carefully the posts you linked in your answer and now I understood the behaviour of solve function.
Thank you again.
Stefano
before posting my question I read only this post http://en.smath.info/forum/default.aspx?g=posts&t=434, so I supposed that the need for an interval was only for non linear equation. I read carefully the posts you linked in your answer and now I understood the behaviour of solve function.
Thank you again.
Stefano
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